if we are considering tertiary alkyl halide ,for reaction ,then due to steric hindrance of three alkyl groups ,sn2 reaction ,substitution does not take place , instead ,there exists greater possibility of elemination reaction , leaing to elemination product. R part of R2CuLi acts as a strong conjugate base and this leeds to elemination
if we are considering tertiary alkyl halide ,for reaction ,then due to steric hindrance of three alkyl groups ,sn2 reaction ,substitution does not take place , instead ,there exists greater possibility of elemination reaction , leaing to elemination product. R part of R2CuLi acts as a strong conjugate base and this leeds to elemination
Very obvious and precise explanation... Thank you...
ReplyDeletei am glad that this explination for corey house synthesis
Deletewas usefull to you
psk chakravarthy
can methane be prepared by this method???
ReplyDeleteno miss shruti .coreyhoyse synthesis requires a minimum of 2 carbons
ReplyDeleteDoes Corey house synthesis always give a substitution product ? Even if R is a tertiary alkyl ?
ReplyDeleteDoes Corey house synthesis always give a substitution product ? Even if R is a tertiary alkyl ?
ReplyDeleteif we are considering tertiary alkyl halide ,for reaction ,then
Deletedue to steric hindrance of three alkyl groups ,sn2 reaction ,substitution does not take place , instead ,there exists greater possibility of elemination reaction , leaing to elemination product. R part of R2CuLi acts as a strong conjugate base and this leeds to elemination
if we are considering tertiary alkyl halide ,for reaction ,then
Deletedue to steric hindrance of three alkyl groups ,sn2 reaction ,substitution does not take place , instead ,there exists greater possibility of elemination reaction , leaing to elemination product. R part of R2CuLi acts as a strong conjugate base and this leeds to elemination
Can alkanes with even no of carbons be formed or mixture obtained
ReplyDeleteYes. Yes it can
Delete